1621B - Integers Shop - CodeForces Solution


data structures greedy implementation *1500

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C++ Code:

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <algorithm>
#include <cmath>
#include <vector>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <queue>
#include <ctime>
#include <cassert>
#include <complex>
#include <string>
#include <cstring>
#include <chrono>
#include <random>
#include <bitset>
#include <array>
using namespace std;

#pragma GCC optimize("Ofast,unroll-loops") 
#pragma GCC target("avx,avx2,fma") 

#define ar array
#define ll long long
#define ld long double
#define sza(x) ((int)x.size())
#define all(a) (a).begin(), (a).end()

#define PI 3.1415926535897932384626433832795l 
const int MAX_N = 1e5 + 5;
const ll MOD = 1e9 + 7;
const ll INF = 1e9;
const ld EPS = 1e-9;

void solve() {
    int n;
    cin >> n;
 
    const int A = 1e9 + 1;
    int minL = A, costL = A;
    int maxR = 0, costR = A;
    int maxLen = 0, costLen = A;
    for (int i = 0; i < n; i++)
    {
        int l, r, c;
        cin >> l >> r >> c;
 
        if (l < minL)
            minL = l, costL = A;
        if (l == minL)
            costL = min(costL, c);
 
        if (maxR < r)
            maxR = r, costR = A;
        if (maxR == r)
            costR = min(costR, c);
 
        if (maxLen < r - l + 1)
            maxLen = r - l + 1, costLen = A;
        if (maxLen == r - l + 1)
            costLen = min(costLen, c);
 
        int ans = costL + costR;
        if (maxLen == maxR - minL + 1)
            ans = min(ans, costLen);
        cout << ans << "\n";
    }
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0); cout.tie(0);
    int tc = 1;
    cin >> tc;
    for (int t = 1; t <= tc; t++) {
        solve();
    }
}


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